If $z_1$ lies on $|z|=r$, then equation of tangent at $z_1$ is

$\frac{z}{\bar{z}_1}+\frac{\bar{z}}{z_1}=r$

$\frac{z}{\bar{z}_1}+\frac{\bar{z}}{z_1}=2$

$\frac{z}{z_1}+\frac{\bar{z}}{\bar{z}_1}=r$

JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

z_1

lies on

|z|=r

, then equation of tangent at

z_1

View answer and explanation

Correct option: A

\frac{z}{z_1}+\frac{\bar{z}}{\bar{z}_1}=2

Option A (

\frac{{z}}{{z_1}}+\frac{{\bar{z}}}{{\bar{z}_1}}=2

) is correct because it represents the equation of the tangent to the circle

|z|=r

at the point

z_1

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