JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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Application +4 | -1

If the mass of an electron is

9.11 \times {10^{ - 31}}\,{\text{kg}},

and uncertainty in position is

{10^{ - 8}}{\text{m}},

the uncertainty in velocity would be:

View answer and explanation

Correct option: B

5.8 \times {10^3}{\text{m}}{{\text{s}}^{ - 1}}

Option B (

5.8 \times {10^3}\,{\text{m}}{{\text{s}}^{ - 1}}

) is correct because it is calculated using the Heisenberg uncertainty principle.

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n^{\text {th }}

\mathrm{A}

\times 10^{12}

\frac{1}{{ }^{\prime} \mathrm{B}^{\prime}}

\ell = 1,\,\,m = 0

1.25 \times {10^{ - 13}} \times {A^{1/3}}\mathrm{cm}.