JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1

e

is the electronic charge,

c

is the speed of light in free space and

h

is Planck’s constant, the quantity

\frac{1}{{4\pi { \in _0}}}\frac{{{{\left| e \right|}^2}}}{{hc}}

has dimensions of

View answer and explanation

Correct option: C

\left[ {{M^0}{L^0}{T^0}} \right]

Option A (

\frac{\pi}{6}

) is correct because the phase difference is calculated by converting both SHMs to sine functions and then subtracting their phase angles.

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{\varepsilon _0}L\frac{{\Delta V}}{{\Delta t}},\;

{\varepsilon _0}

{\Delta V}

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