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JEE MATHEMATICS MCQ: PARABOLA

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Application +4 | -1
The angle between the tangents drawn from the point (3,4)\left( {3,4} \right) to the parabola y2−2y+4x=0{y^2} - 2y + 4x = 0 is
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Correct option: A
tan⁡−1(85/7){\tan ^{ - 1}}\left( {8\sqrt 5 /7} \right)
Option A (tan⁡−1(85/7){\tan ^{ - 1}}\left( {8\sqrt 5 /7} \right)) is correct because it is the angle between the tangents calculated using the properties of the parabola and the tangent equation.

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The equation of a common tangent to the parabolas y=x2y=x^2 and y=−(x−2)2y=-(x-2)^2 is A point PP moves such that slope of one tangent drawn from it to parabola y2=16xy^2=16 x is four times the slope of other tangent, then the length of latus rectum of the conic represented by locus of PP, is Let P,Q,RP,Q,R be three points on parabola y2=4x{y^2} = 4x and normal at PP and RR meet at QQ, then the locus of the mid-point of the chord PRPR is a parabola whose vertex is at The tangents at the end points of any chord through (1,0)(1,0) to the parabola y2+4x=8y^2+4 x=8 intersect The focus of the parabola x2=−16yx^2=-16 y is If II denotes the semi-latusrectum of the parabola y2=4ax{y^2} = 4ax and SPSP and SQSQ denote the segments of any focal chord PQ,SPQ,S being the focus, then SP,lSP,l and SQSQ are in the relation
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