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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy
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Application +4 | -1
If cos⁡A3=cos⁡B4=15−π2<A<0\frac{\cos A}{3}=\frac{\cos B}{4}=\frac{1}{5}-\frac{\pi}{2} < A < 0 and −π2<B<0-\frac{\pi}{2} < B < 0, then the value of 2sin⁡A+4sin⁡B2 \sin A+4 \sin B is
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Correct option: C
−4-4
Option C (-4) is correct because it is the result of calculating 2sin⁡A+4sin⁡B2 \sin A + 4 \sin B using the given conditions and quadrant information.

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