JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Analyzing +4 | -1

I_n=\int_0^\pi \frac{1-\sin 2 n x}{1-\cos 2 x} d x

, then

I_1, I_2, I_3, \ldots

are in

View answer and explanation

Correct option: A

Option A (AP) is correct because the difference between consecutive terms

I_{n+1} - I_n

is constant, indicating an arithmetic progression.

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