JEE PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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A bus starts from rest and moves along a straight road with constant acceleration

f

until its speed is

v

. The bus then continues with constant speed

v

. When the bus starts, a car is at a distance

b

behind the bus and is moving with constant speed

u

in same direction as that of bus. Find the distance between the car and the bus at time

t

after the bus started.

(Given

0 < t < \frac{v}{f}

and

u^2 < 2 f b

View answer and explanation

Correct option: A

b-u t+\frac{f t^2}{2}

Option A (

b-u t+\frac{f t^2}{2}

) is correct because it represents the difference between the initial distance, the distance covered by the car, and the distance covered by the bus with constant acceleration.

More Questions from MOTION IN A STRAIGHT LINE

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Assertion: In a free fall, the initial velocity of a body may not be zero.
Reason: Free fall means the vertical acceleration of the body is equal to

\mathrm{g}

. A ball is thrown vertically upward with speed 15 m/s and it returns to the ground with speed 10 m/s as a constant air resistance acts. The maximum height attained by the ball is Which of the following is not a derived quantites? Assertion: If a body is dropped from the top of a tower of height

\mathrm{h}

and another body is thrown up simultaneously with velocity

\mathrm{u}

from the foot of the tower, then both of them would meet after a time

\frac{\mathrm{h}}{\mathrm{u}}

.
Reason: For a body projected upwards, the distance covered by the body in the last second of its upward journey is always

4.9 \mathrm{~m}

irrespective of velocity of projection.

(\mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^2)

A particle is having uniform acceleration. If its displacement from

t

(t+1)

second is

120 \mathrm{~m}

and change in velocity is

50 \mathrm{~m} / \mathrm{s}

. Find its displacement (in

\mathrm{m}

) in

(t+2)

second. An aeroplane flies 400m north and 300m south and then flies 1200m upwards, then net displacement is