The value of $\mathop {\lim }\limits_{x \to 0} \left\{ {\frac{{\sin x - x + \frac{{{x^3}}}{6}}}{{{x^5}}}} \right\}$ is

JEE MATHEMATICS MCQ: LIMITS

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Application +4 | -1

The value of

\lim\limits_{x \to 0} \left\{ {\frac{{\sin x - x + \frac{{{x^3}}}{6}}}{{{x^5}}}} \right\}

View answer and explanation

Correct option: D

\frac{1}{{120}}

Option D (

\frac{1}{{120}}

) is correct because it is the result of evaluating the limit using the Taylor series expansion of sin(x).

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