JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

\left( {1 - p} \right)\left( {1 + 2x + 4{x^2} + 8{x^3} + 16{x^4} + 32{x^5}} \right) = 1 - {p^6},p \ne 1

then a value of

p/x

View answer and explanation

Correct option: B

Option B (2) is correct because by simplifying the given equation, we find that p = 2x, hence p/x = 2.

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