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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Sum of the first nn terms of the series 12+34+78+1516+…\frac{1}{2}+\frac{3}{4}+\frac{7}{8}+\frac{15}{16}+\ldots is equal to
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Correct option: C
n+2−n−1n+2^{-n}-1
Option C (n+2−n−1n+2^{-n}-1) is correct because the sum can be rewritten as a difference of 1 and a geometric progression, which simplifies to the given expression.

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