NEET UG PHYSICS MCQ: THERMODYNAMICS

1 Hard

1 of 1

Application +4 | -1

A bullet of mass

m \mathrm{~kg}

is moving with velocity

K^2 \, \mathrm{m} / \mathrm{s}

collides against a vertical wall, consequently half of its kinetic energy is converted into heat. If whole heat is acquired by the bullet, the rise in temperature

\text{(in }{ }^{\circ} \mathrm{C})

of bullet is

\text{(specific heat for bullet }=s \mathrm{~J} / \mathrm{kg}^{\circ} \mathrm{C})

View answer and explanation

Correct option: B

\frac{K^4}{4 s}

Option B (

\frac{K^4}{4 s}

) is correct because it is the rise in temperature calculated from the kinetic energy converted to heat.

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