JEE MATHEMATICS MCQ: MULTIPLE AND SUBMULTIPLE ANGLES

1 Easy

1 of 1

Application +4 | -1

The value of

\cos \frac{\pi }{{{2^2}}} \cdot \cos \frac{\pi }{{{2^3}}}.......\cos \frac{\pi }{{{2^{10}}}} \cdot \sin \frac{\pi }{{{2^{10}}}}

View answer and explanation

Correct option: C

\frac{1}{{512}}

Option C (

\frac{1}{{512}}

) is correct because it is the simplified result after applying the trigonometric identity for the product of cosines and sine.

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