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JEE PHYSICS MCQ: MAGNETIC EFFECT OF CURRENT

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The magnetic field applied on a cyclotron is 3.5 T3.5 {~T}. What will be the frequency of electric field that must be applied between the Dee's in order to accelerate a proton?
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Correct option: C
5.57×107 Hz5.57 \times 10^7 {~Hz}
Option C (5.57×107 Hz5.57 \times 10^7 {~Hz}) is correct because the frequency of the electric field is calculated using the magnetic field and the charge-to-mass ratio of the proton.

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