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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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If 3sin⁡2θ+2sin⁡2ϕ=13 \sin ^2 \theta+2 \sin ^2 \phi=1 and 3sin⁡2θ=2sin⁡2ϕ,0<θ<π23 \sin 2 \theta=2 \sin 2 \phi, 0 < \theta < \frac{\pi}{2} and 0<ϕ<π20 < \phi < \frac{\pi}{2}, then the value of θ+2ϕ\theta+2 \phi is
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Correct option: A
π2\frac{\pi}{2}
Option A (π2\frac{\pi}{2}) is correct because after simplification and using trigonometric identities, θ+2ϕ\theta + 2\phi equals π2\frac{\pi}{2}.

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