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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Hard
1 of 1
Analyzing +4 | -1
If I1=∫0π/2cos⁡(sin⁡x)dx,I2=∫0π/2sin⁡(cos⁡x)dxI_1=\int_0^{\pi / 2} \cos (\sin x) d x, I_2=\int_0^{\pi / 2} \sin (\cos x) d x and I3=∫0π/2cos⁡xdxI_3=\int_0^{\pi / 2} \cos x d x, then
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Correct option: A
I1>I3>I2I_1>I_3>I_2
Option C (I1>I2>I3I_1>I_2>I_3) is incorrect. The correct order is I1>I3>I2I_1 > I_3 > I_2 because cos⁡(sin⁡x)>cos⁡x\cos(\sin x) > \cos x and cos⁡x>sin⁡(cos⁡x)\cos x > \sin(\cos x) for x∈(0,π/2)x \in (0, \pi/2).

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