JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

S_n=\sum\limits_{{r=1}}^n \frac{1+2+2^2+\ldots \text { upto } r \text { terms }}{2^r}

, then

S_n

is equal to

View answer and explanation

Correct option: C

n-1+\frac{1}{2^n}

Option C (

n-1+\frac{1}{2^n}

) is correct because the sum of the geometric series is calculated and simplified correctly.

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