If $A=\{x: x=3 n, n \in Z\}$ and $B=\{x: x=4 n, n \in Z\}$ then $A \cap B$ is

$\{{x}: {x}={n}, {n} \in {Z}\}$

$\{{x}: {x}={n} / 2, {n} \in {Z}\}$

$\{{x}: {x}={n}-1, {n} \in {Z}\}$

JEE MATHEMATICS MCQ: SET THEORY

1 Easy

1 of 1

Understanding +4 | -1

A=\{x: x=3 n, n \in Z\}

and

B=\{x: x=4 n, n \in Z\}

then

A \cap B

View answer and explanation

Correct option: D

\{{x}: {x}=12 {n}, {n} \in {Z}\}

Option D is correct because A contains multiples of 3, B contains multiples of 4, and their intersection contains multiples of both 3 and 4, which are multiples of 12.

More Questions from SET THEORY

Practice All Chapter MCQs →

Let

S

be the set of all those 2007-place decimal integers

2 a_1 a_2 a_3 \ldots . . a_{2006}

which contain odd number of digit 9 in each sequence

a_1, a_2, a_3, \ldots ., a_{2006}

. The cardinal number of

S

is If

a N=\{a n: n \in N: b N=\{n b: n \in N\}

c N=\{c N: n \in N\}

and

b N \cap c N=d N

, where

a, b, c \in N

and

b, c

are coprime, then Which of the following cannot be the number of elements in the power set of any finite set? If

A=\{x: x

is a multiple of 3

\}

and

B=\{x: x

is a multiple of 5}, then

A-B

is equal to If

F(n)

denotes the set of all divisors of

n

except 1 , what is the least value of y satisfying

[\mathrm{F}(20) \cap \mathrm{F}(16)] \subseteq \mathrm{F}(\mathrm{y})

? In a town of 10000 families, it was found that

40 \%

families buy newspaper

A, 20 \%

families buy newspaper B and

10 \%

families buy newspaper

C

, 5% families buy newspapers

A

and B, 3% buy newspapers B and

C

and

4 \%

buy newspapers

A

and

C

. If

2 \%

families buy all the three newspapers, then number of families which buy

A

only is