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JEE CHEMISTRY MCQ: HYDROCARBONS

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Which of the following will decolourise alkaline

\mathrm{KMnO}_4

solution?

View answer and explanation

Correct option: D

\mathrm{C}_2 \mathrm{H}_4

Option D (

\mathrm{C}_2 \mathrm{H}_4

) is correct because it is an unsaturated compound (alkene) that can react with and decolorize alkaline

\mathrm{KMnO}_4

solution via oxidation.

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\mathrm{Ca}{\mathrm{C}_2} + {\mathrm{H}_2}\mathrm{O} \to X\xrightarrow{{{\mathrm{O}_3}/\frac{{{\mathrm{H}_2}\mathrm{O}}}{{\mathrm{O}{\mathrm{H}^ + }}}}}\mathrm{HCOOH} + \mathrm{HCOOH},X\;\mathrm{is}

In benzene, there is a delocalisation of π-electrons. Hence, each π-electron is attached by….carbon nuclei. Which statement is false? Assertion (A) In comparison to ethyl chloride, it is not easy to carry outnucleophilic substitution on vinyl chloride.

Reason (R) Vinyl group is an electron donating. If 2-oxopropanal and methanal are obtained by the reductive ozonolysis of compound (A), then the number of

\sigma

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