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NEET UG PHYSICS MCQ: GRAVITATION

1 Easy

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Application +4 | -1

The percentage decrease in the weight of a rocket, when taken to a height of

32 \mathrm{~km}

above the surface of earth will, be:

(Radius of earth

=6400 \mathrm{~km}

)

View answer and explanation

Correct option: A

1 \%

Option A (

1 \%

) is correct because the percentage decrease in weight is approximately

2h/R

, where h is the height above the Earth's surface and R is the Earth's radius. So, (2 * 32)/6400 = 0.01 or 1%.

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