JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

Area bounded between

y=x \cdot e^{-x^2}, y=0

and max. ordinate is

View answer and explanation

Correct option: C

\frac{1}{2}\left(1-\frac{1}{\sqrt{{e}}}\right)

Option C (

\frac{{1}}{{2}}\left(1-\frac{{1}}{{\sqrt{{{e}}}}\right)

) is correct because it is the area bounded between the curve and the x-axis up to the maximum ordinate.

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