Skip to main content
Back to THERMODYNAMICS

JEE PHYSICS MCQ: THERMODYNAMICS

1 Medium
1 of 1
Remembering +4 | -1
The relation between two specific heats of a gas is
View answer and explanation
Correct option: A
CP−CV=RJ{C_P} - {C_V} = \frac{R}{J}
Option A (CP−CV=RJ{C_P} - {C_V} = \frac{R}{J}) is correct because it represents the relationship between specific heat at constant pressure, specific heat at constant volume, the gas constant, and the mechanical equivalent of heat.

More Questions from THERMODYNAMICS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.