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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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The energy of an electron in nthΒ {n}^{\text {th }} orbit of hydrogen atom is
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Correct option: C
13.6n2eV\frac{13.6}{n^2} \mathrm{eV}
Option C (13.6n2eV\frac{{13.6}}{{n^2}} \mathrm{{eV}}) is correct because the energy of an electron in the nth orbit of a hydrogen atom is given by the formula E=βˆ’13.6/n2E = -13.6/n^2 eV.

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