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JEE PHYSICS MCQ: ELECTRIC POTENTIAL AND CAPACITANCE

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Application +4 | -1

An electric field is expressed as

E=2 \hat{i}+3 \hat{j}

. Find the potential difference

\left(V_A-V_B\right)

between two points

A

and

B

whose position vectors are given by

r_A=\hat{i}+2 \hat{j}

and

r_B=2 \hat{i}+\hat{j}+3 \hat{k}

.

View answer and explanation

Correct option: A

-1 V

Option A (-1 V) is correct because the potential difference is calculated by integrating the electric field along the displacement vector.

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