JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Analyzing +4 | -1

\lim \limits_{{h \rightarrow 0}}\left\{\frac{1}{h \cdot \sqrt[3]{8+h}}-\frac{1}{2 h}\right\}

is equal to

View answer and explanation

Correct option: D

-\frac{1}{48}

Option D (-1/48) is correct because after simplifying the expression and using L'Hopital's rule or series expansion, the limit evaluates to -1/48.

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