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JEE MATHEMATICS MCQ: LIMITS

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Application +4 | -1
lim⁑xβ†’0(cos⁑x)cot⁑2x\lim \limits_{{x \rightarrow 0}}(\cos x)^{\cot ^2 x} is
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Correct option: D
1e\frac{1}{\sqrt{e}}
Option D (1e\frac{{1}}{{\sqrt{{e}}}}) is correct because by applying L'HΓ΄pital's rule to the logarithmic form of the limit, we find the limit to be eβˆ’12=1ee^{-\frac{{1}}{{2}}} = \frac{{1}}{{\sqrt{{e}}}}.

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