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NEET UG CHEMISTRY MCQ: STRUCTURE OF ATOM

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Application +4 | -1

The frequency of radiation emitted when the electron falls from n=4 to n=1 in a hydrogen atom will be (Given, ionisation energy of

103\,H = 2.18 \times {10^{ - 18}}\mathrm{\;J\;ato}{\mathrm{m}^{ - 1}}\mathrm{\;and\;}h = 6.625 \times {10^{ - 34}}\mathrm{\;Js}

View answer and explanation

Correct option: C

3.08 \times {10^{15}}{\mathrm{s}^{ - 1}}

Option C (

3.08 \times {10^{15}}{\mathrm{s}^{ - 1}}

) is correct because the frequency is calculated using the energy difference between the levels and Planck's constant.

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