A stone falls from a balloon that is descending at a uniform rate of $12{\rm{m}}{{\rm{s}}^{ - 1}}$. The displacement of the stone from the point of release after 10s is

NEET UG PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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A stone falls from a balloon that is descending at a uniform rate of

12\mathrm{m}{\mathrm{s}^{ - 1}}

. The displacement of the stone from the point of release after 10s is

View answer and explanation

Correct option: B

610 m

Option B (610 m) is correct because it is calculated using the equation of motion

s = ut + \frac{1}{2}at^2

with the initial velocity being the descending rate of the balloon.

Practice All Chapter MCQs →

8 \mathrm{~m} / \mathrm{s}

30\mathrm{km}{\mathrm{h}^{ - 1}}

1 \mathrm{~ms}^{-2}

150 \mathrm{~m}

2 \mathrm{~ms}^{-2}

{V_1} = 10\,kmph

{V_2} = 20\,kmph

{V_3} = 60\,kmph