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JEE CHEMISTRY MCQ: HYDROCARBONS

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Analyzing +4 | -1
In the reaction C2H6→(CH3COO)2MnA→NaOHB,{C_2}{H_6}\xrightarrow{{{{\left( {C{H_3}COO} \right)}_2}Mn}}A\xrightarrow{{NaOH}}B, the correct statement about BB is
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Correct option: D
Both 1 and 2
Option D is correct because after the given reactions, A is acetic acid and B is sodium acetate, which on decarboxylation gives methane and on Kolbe's electrolysis gives ethane.

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