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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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O2\mathrm{O}_2 undergoes photochemical dissociation into one normal oxygen atom and one oxygen atom, 1.2 eV\mathrm{eV} more energetic than normal. The dissociation of O2\mathrm{O}_2 into two normal atoms of oxygen requires 482.5 kJ/mol482.5 \mathrm{~kJ} / \mathrm{mol}. The maximum wavelength effective for photochemical dissociation of O2\mathrm{O}_2 is (1eV=(1 \mathrm{eV}= 96.5 kJ/mol96.5 \mathrm{~kJ} / \mathrm{mol} )
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Correct option: D
200 nm200 \mathrm{~nm}
Option D (200 nm) is correct because it is calculated by finding the total energy required for dissociation and then using that energy to determine the maximum wavelength.

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