JEE MATHEMATICS MCQ: STRAIGHT LINES

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Application +4 | -1

The slopes of the lines joining the origin to the points of trisection of the portion of the line

3x + y = 12

intercepted between the axis are the roots of the equation

View answer and explanation

Correct option: A

2{x^2} - 15x + 18 = 0

Option A (

2{x^2} - 15x + 18 = 0

) is correct because it represents the quadratic equation whose roots are the slopes of the lines joining the origin to the points of trisection of the given line segment.

More Questions from STRAIGHT LINES

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If the three lines

x-3 y=p, a x+2 y=q

and

a x+y=r

form a right-angled triangle then :
The orthocentre of the triangle whose vertices are

\left\{ {a{t_1}{t_2},\;a\left( {{t_1} + {t_2})\} ,\{ a{t_2}{t_3},a({t_2} + {t_3}} \right)} \right\},\;\left\{ {a{t_3}{t_1},\;a\left( {{t_3} + {t_1}} \right)} \right\}

is
The distance between the parallel lines

y = 2\;x + 4

and

6x = 3y + 5

is The distance between the pair of lines given by

{x^2} + {y^2} + 2xy - 8ax - 8ay - 9{a^2} = 0

is Find the image of the point

(3,8)

with respect of the line

x+3 y=7

assuming the line to be plane mirror: The centroid of the triangle whose three sides are given by the combined equation

\left( {{x^2} + 7xy + 2{y^2}} \right)\left( {y - 1} \right) = 0