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JEE PHYSICS MCQ: MAGNETIC EFFECT OF CURRENT

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Application +4 | -1
A particle moving in a circle of radius RR with a uniform speed takes a time TT to complete one revolution. If this particle were projected with the same speed at an angle 'θ\theta' to the horizontal, the maximum height attained by it equals 4R.4R. The angle of projection 'θ\theta' is then given by:
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Correct option: B
θ=sin⁡−1(2gT2π2R)12\mathrm{\theta } = {\sin ^{ - 1}}{\left( {\frac{{2g{T^2}}}{{{\pi ^2}R}}} \right)^{\frac{1}{2}}}
Option B (θ=sin⁡−1(2gT2π2R)12\mathrm{\theta } = {\sin ^{ - 1}}{\left( {\frac{{2g{T^2}}}{{{\pi ^2}R}}} \right)^{\frac{1}{2}}}) is correct because it correctly relates the angle of projection to the time period, radius, and acceleration due to gravity.

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