JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Application +4 | -1

The angles of elevation of a vertical tower standing inside a triangular field at the vertices of the field are each equal to

\theta

. If the length of the sides of the field are

30 \mathrm{~m}, 50 \mathrm{~m}

and

70 \mathrm{~m}

, the height of the tower is

View answer and explanation

Correct option: B

(70 / \sqrt{3}) \tan \theta \mathrm{m}

Option B (

(70 / \sqrt{3}) \tan \theta \mathrm{m}

) is correct because it is derived by finding the circumradius of the triangle and relating it to the height of the tower and the angle of elevation.

More Questions from PROPERTIES OF TRIANGLES

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{p_1},{p_2},{p_3}

\Delta \;ABC

A,B,C

\Delta

p_1^{ - 2} + p_2^{ - 2} + p_3^{ - 2}

5k,\;6k,\;5k

k

\Delta \,ABC

a = \left( {b - c} \right)\sec \theta

\frac{{2\,\sqrt {bc} }}{{b - c}}\,\,\sin \,\,\frac{A}{2} =

\Delta \;ABC,\frac{{b + c}}{a}

\Delta = {a^2} - {\left( {b - c} \right)^2}

\Delta

\Delta \;ABC

\tan A

A

2 s