JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Application +4 | -1

\lim\limits_{x \to \infty } \frac{{{{\left( {2x + 1} \right)}^{40}}{{\left( {4x - 1} \right)}^5}}}{{{{\left( {2x + 3} \right)}^{45}}}}

is equal to

View answer and explanation

Correct option: C

Option C (32) is correct because after factoring out

x

and simplifying, the limit evaluates to 32.

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