The value of $\mathop \smallint \nolimits_1^2 \,\,\frac{{dx}}{{\left( {x + 1} \right)\,\,\sqrt {{x^2} - 1} }}$ is

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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The value of

\int \nolimits_1^2 \,\,\frac{{dx}}{{\left( {x + 1} \right)\,\,\sqrt {{x^2} - 1} }}

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Correct option: B

\frac{1}{{\sqrt 3 }}

The correct answer is 1/√(3) because after substituting x = sec θ and evaluating the definite integral, we obtain this value.

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