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NEET UG PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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Application +4 | -1
The position of a particle x (in metres) at a time t seconds is given by the relation r⃗=(3ti^−t2j^+4k^)\vec r = \left( {3t\hat i - {t^2}\hat j + 4\hat k} \right). Calculate the magnitude of velocity of the particle after 5 seconds
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Correct option: D
10.44
Option D (10.44) is correct because it is the magnitude of the velocity vector calculated by differentiating the position vector and substituting t=5s.

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