NEET UG PHYSICS MCQ: WORK-ENERGY-POWER

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Application +4 | -1

A force of 5N, making an angle

\theta

with the horizontal, acting on an object displaces it by 0.4m along the horizontal direction. If the object gains kinetic energy of 1J, the horizontal component of the force is

View answer and explanation

Correct option: B

2.5 N

Option B (2.5 N) is correct because the horizontal component of the force is calculated using the work-energy theorem:

W = Fx\cos\theta = \Delta KE

, where

Fx\cos\theta

is the horizontal component of the force.

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