JEE PHYSICS MCQ: MOTION IN PLANE

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Application +4 | -1

Two vectors are given by

\vec{A}=(3 \hat{i}+\hat{j}+3 \hat{k})

and

\vec{B}=(3 \hat{ i }+5 \hat{ j }-2 \hat{ k })

. Find the third vector

\vec{ C }

\vec{ A }+3 \vec{ B }-\vec{ C }=0

View answer and explanation

Correct option: C

(12 \hat{i}+16 \hat{j}-3 \hat{k})

Option C (

(12 \hat{i}+16 \hat{j}-3 \hat{k})

) is correct because it is the result of the vector addition and scalar multiplication as described in the equation

\vec{C} = \vec{A} + 3\vec{B}

More Questions from MOTION IN PLANE

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\mathrm{\vec P} = \mathrm{\vec A} + \mathrm{\vec B}\,\,\mathrm{and}\,P = A + B.

\mathrm{\vec A}\,and\,\mathrm{\vec B}

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\mathrm{If}\,(\mathbf{a}+3 \mathbf{b}) \cdot(7 \mathbf{a}-5 \mathbf{b})=0

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