JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

Let

f\left( x \right) = \int \nolimits_1^x \,\,\sqrt {2\,\, - \,\,{t^2}} \,dt

.〗 Then, real roots of the equation

{x^2} - f'\left( x \right) = 0

are

View answer and explanation

Correct option: A

\pm \,\,1

Option A (

\pm \,\,1

) is correct because these are the real roots obtained by solving the equation

{x^2} - f'\left( x \right) = 0

after finding

f'(x)

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