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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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The electrostatic force (F→1)\left(\overrightarrow{\mathrm{F}}_1\right) and magnetic force (F→2)\left(\overrightarrow{\mathrm{F}}_2\right) acting on a charge q\mathrm{q} moving with velocity v\mathrm{v} can be written:
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Correct option: C
F→1=qE→,F→2=q(V→×B→)\overrightarrow{\mathrm{F}}_1=\mathrm{q} \overrightarrow{\mathrm{E}}, \overrightarrow{\mathrm{F}}_2=\mathrm{q}(\overrightarrow{\mathrm{V}} \times \overrightarrow{\mathrm{B}})
Option C (F→1=qE→,F→2=q(V→×B→)\overrightarrow{\mathrm{F}}_1=\mathrm{q} \overrightarrow{\mathrm{E}}, \overrightarrow{\mathrm{F}}_2=\mathrm{q}(\overrightarrow{\mathrm{V}} \times \overrightarrow{\mathrm{B}})) is correct because the electrostatic force is given by qEqE and the magnetic force by q(v×B)q(v \times B).

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