Skip to main content
Back to ELECTROMAGNETIC WAVES

JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

1 Medium
1 of 1
Understanding +4 | -1
A parallel plate capacitor is charged to 60μC60\mathrm{\mu C}. Due to a radioactive source, the plate loss charge at the rate of 1.8  ×  10−8  Cs−1.1.8\mathrm{\;} \times \mathrm{\;}{10^{ - 8}}\mathrm{\;C}{\mathrm{s}^{ - 1}}. The magnitude of displacement current is
View answer and explanation
Correct option: A
1.8×10−8  Cs−11.8 \times {10^{ - 8}}\mathrm{\;C}{\mathrm{s}^{ - 1}}
Option A (1.8×10−8  Cs−11.8 \times {10^{ - 8}}\mathrm{\;C}{\mathrm{s}^{ - 1}}) is correct because the displacement current is equal to the rate of change of charge on the capacitor plates.

More Questions from ELECTROMAGNETIC WAVES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.