JEE MATHEMATICS MCQ: SET THEORY

1 Easy

1 of 1

Application +4 | -1

A = \left\{ {\left( {x,y} \right)\;:y = \frac{4}{x},x \ne 0} \right\}

and

B = \left\{ {\left( {x,y} \right):{x^2} + {y^2} = 8,x,y \in R} \right\}

, then

View answer and explanation

Correct option: C

A \cap B

contains two points only

The correct answer is C (

A \cap B

contains two points only) because solving the system of equations y = 4/x and x² + y² = 8 yields two intersection points.

More Questions from SET THEORY

Practice All Chapter MCQs →

S

2 a_1 a_2 a_3 \ldots . . a_{2006}

a_1, a_2, a_3, \ldots ., a_{2006}

S

a N=\{a n: n \in N: b N=\{n b: n \in N\}

c N=\{c N: n \in N\}

b N \cap c N=d N

a, b, c \in N

b, c

A=\{x: x

\}

B=\{x: x

A-B

F(n)

n

[\mathrm{F}(20) \cap \mathrm{F}(16)] \subseteq \mathrm{F}(\mathrm{y})

40 \%

A, 20 \%

10 \%

C

A

C

4 \%

A

C

2 \%

A