JEE MATHEMATICS MCQ: MULTIPLE AND SUBMULTIPLE ANGLES

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Application +4 | -1

The value of

\cos A \cos 2 A \cos 2^2 A \cos 2^3 A \ldots \cos 2^{n-1} A

View answer and explanation

Correct option: B

\frac{\sin 2^n A}{2^n \sin A}

Option B is correct because the given expression can be simplified using the identity

2 \sin A \cos A = \sin 2A

repeatedly.

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