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JEE MATHEMATICS MCQ: ELLIPSE

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Analyzing +4 | -1
The normals at four points on the ellipse x2a2+y2b2=1\frac{x^2}{a^2}+\frac{y^2}{b^2}=1 meet in the point (h,k)(h, k). Then, the mean position of the four points is
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Correct option: D
(a2h2(a2−b2),b2k2(a2−b2))\left(\frac{a^2 h}{2\left(a^2-b^2\right)}, \frac{b^2 k}{2\left(a^2-b^2\right)}\right)
Option D is correct because the mean position is derived from the properties of normals to the ellipse and the equation of the ellipse itself.

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