The correct order of decreasing boiling points of ${\rm{C}}{{\rm{H}}_3}{\rm{CON}}{{\rm{H}}_2}\;(A),{\rm{C}}{{\rm{H}}_3}{\rm{COCl}}\;(B),{\rm{C}}{{\rm{H}}_3}{\rm{COOH}}\;{\rm{(C),}}\;{\rm{and}}\,{\left( {{\rm{C}}{{\rm{H}}_3}{\rm{CO}}} \right)_2}{\rm{O}}\;(D),$ is:

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JEE CHEMISTRY MCQ: ALDEHYDES & KETONES & CARBOXYLIC ACIDS

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The correct order of decreasing boiling points of

\mathrm{C}{\mathrm{H}_3}\mathrm{CON}{\mathrm{H}_2}\;(A),\mathrm{C}{\mathrm{H}_3}\mathrm{COCl}\;(B),\mathrm{C}{\mathrm{H}_3}\mathrm{COOH}\;\mathrm{(C),}\;\mathrm{and}\,{\left( {\mathrm{C}{\mathrm{H}_3}\mathrm{CO}} \right)_2}\mathrm{O}\;(D),

is:

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Correct option: A

A > D > C > B

Option A (

A > D > C > B

) is correct because the boiling points are determined by intermolecular forces: amides have strong hydrogen bonding, followed by anhydrides, carboxylic acids (dimer formation), and then acyl chlorides.

JEE CHEMISTRY MCQ: ALDEHYDES & KETONES & CARBOXYLIC ACIDS

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