$\mathop {\lim }\limits_{h \to 0} \frac{{\sin \sqrt {x + h} - \sin \sqrt x }}{h}$ is equal to

$1/\left( {2\sin \sqrt x } \right)$

JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Application +4 | -1

\lim\limits_{h \to 0} \frac{{\sin \sqrt {x + h} - \sin \sqrt x }}{h}

is equal to

View answer and explanation

Correct option: C

\left( {\cos \sqrt x } \right)/2\sqrt x

Option C (

\left( {\cos \sqrt x } \right)/2\sqrt x

) is correct because applying L'Hopital's rule to the limit results in this expression.

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