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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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Two similarly equally charged identical metal spheres AA and BB repel each other with a force of 2.0Γ—10βˆ’5Β N2.0 \times 10^{-5} \mathrm{~N}. AA third identical uncharged sphere CC is touched to AA, then placed at the midpoint between AA and BB. Calculate the net electrostatic force on CC.
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Correct option: B
2.0Γ—10βˆ’5Β N2.0 \times 10^{-5} \mathrm{~N}
Option B (2.0Γ—10βˆ’5Β N2.0 \times 10^{-5} \mathrm{~N}) is correct because it is the net electrostatic force on sphere C, calculated by considering the forces due to spheres A and B.

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