The volume occupied by one molecule of water (density $1\;g\;{\rm{c}}{{\rm{m}}^-3}$ ) is:

$3.0 \times {10^{ - 23}}\;{\rm{c}}{{\rm{m}}^3}$

$6.023 \times {10^{ - 23}}\;{\rm{c}}{{\rm{m}}^3}$

JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

1 Easy

1 of 1

Application +4 | -1

The volume occupied by one molecule of water (density

1\;g\;\mathrm{c}{\mathrm{m}^-3}

) is:

View answer and explanation

Correct option: D

3.0 \times {10^{ - 23}}\;\mathrm{c}{\mathrm{m}^3}

Option D (

3.0 \times {10^{ - 23}}\;\mathrm{c}{\mathrm{m}^3}

) is correct because it is derived from dividing the molar volume of water by Avogadro's number.

Practice All Chapter MCQs →

{H_2}O.

mol\,\,k{g^{ - 1}})

2.24 {~L}

{CH}_4

{CO}_2

0.5 \mathrm{M} \mathrm{H}_2 \mathrm{SO}_4

0.5 \mathrm{~g}

\mathrm{Cu}(\mathrm{II})