JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1

The dimensions of

\;\frac{a}{b}

in the equation

p = \frac{{a\; - \;{t^2}}}{{bx}}

where p is pressure, x is distance and t is time, are

View answer and explanation

Correct option: B

\left[ {\mathrm{M}{\mathrm{T}^{ - 2}}} \right]

Option B

\left[ {\mathrm{M}{\mathrm{T}^{ - 2}}} \right]

is correct because it is derived from dimensional analysis using the principle of homogeneity.

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\left[ {{\mathrm{M}^{ - 1}}{\mathrm{L}^{ - 3}}{\mathrm{A}^2}{T^3}} \right]

{\varepsilon _0}L\frac{{\Delta V}}{{\Delta t}},\;

{\varepsilon _0}

{\Delta V}

{\Delta t}