Back to SEQUENCE OF SERIES
JEE MATHEMATICS MCQ: SEQUENCE OF SERIES
1
Easy
1 of 1
Application
+4 | -1
The sum of a GP with common ratio 3 is 364 and last term is 243, then the number of terms is
View answer and explanation
Correct option: A
6
Option A (6) is correct because it is the number of terms that satisfies the given conditions for the geometric progression.
More Questions from SEQUENCE OF SERIES
Practice All Chapter MCQs →
Given the sets , then find the following
(i)
(ii)
(iii) If are in A.P.; are in G.P. and are in G.P., then are in Suppose is expressed as a polynomial in , as where , then equals If and are in , where and c are in , then are the lengths of sides of If the sum of three numbers in G.P. is 63 and the product of the first and the second term is of the third term, then the numbers are If the lengths of sides of a right angled triangle are in A.P., then their ratio is
(i)
(ii)
(iii) If are in A.P.; are in G.P. and are in G.P., then are in Suppose is expressed as a polynomial in , as where , then equals If and are in , where and c are in , then are the lengths of sides of If the sum of three numbers in G.P. is 63 and the product of the first and the second term is of the third term, then the numbers are If the lengths of sides of a right angled triangle are in A.P., then their ratio is
