NEET UG PHYSICS MCQ: OSCILLATIONS

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Analyzing +4 | -1

A particle, with restoring force proportional to displacement and resisting force proportional to velocity is subjected to a force.

F = {F_0}\sin \omega t

If the amplitude of the particle is maximum for ω=

{\omega _1}

and the energy of the particle is maximum for ω=

{\omega _2}

then

View answer and explanation

Correct option: C

{\omega _1} \ne {\omega _0}\,\,\mathrm{and}\,\,{\omega _2} = {\omega _0}

Option C (

{\omega _1} \ne {\omega _0}\,\mathrm{and}\,{\omega _2} = {\omega _0}

) is correct because the amplitude is maximum near the resonant frequency, but the energy is maximum exactly at the resonant frequency.

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{f_1}

{f_2}

F=-k x^3

(k=

)

f

2 f

2 f.

y_1=10 \sin \left(10 \pi t+\frac{\pi}{3}\right)

y_2=12 \sin \left(8 \pi t+\frac{\pi}{4}\right)

t=0.5 \mathrm{~s}